wayout 寫到：
您好：請問 以下程式碼中
1. set -- "$dir"/* 的
set --
該如何解釋?
set 可以取得 Shell的環境變數
但 set -- ，這又該如何解釋!

2.
for name do
echo $name
done

一般 name 不用做路徑設定，他就會抓該目錄下的 所有檔案嗎?

謝謝!

#/usr/bin/env sh
for name in *; do
echo $name
done

#/usr/bin/env sh
for name in ./*; do
echo $name
done

#/usr/bin/env sh
set -- *
for name do
echo $name
done

#/usr/bin/env sh
set -- ./*
for name do
echo $name
done

$ help for

for: for NAME [in WORDS ... ] ; do COMMANDS; done
Execute commands for each member in a list.

The `for' loop executes a sequence of commands for each member in a
list of items. If `in WORDS ...;' is not present, then `in "$@"' is
assumed. For each element in WORDS, NAME is set to that element, and
the COMMANDS are executed.

Exit Status:
Returns the status of the last command executed.

If `in WORDS ...;' is not present, then `in "$@"' is
assumed.

$ help set

set: set [-abefhkmnptuvxBCHP] [-o option-name] [--] [arg ...]
Set or unset values of shell options and positional parameters.

Change the value of shell attributes and positional parameters, or
display the names and values of shell variables.

Options:


...略...

-- Assign any remaining arguments to the positional parameters.
If there are no remaining arguments, the positional parameters
are unset.

...略...

#/usr/bin/env sh

echo $@

set -- a b c

echo $@

$ ./test.sh 1 2 3

$ bash test.sh 1 2 3

$ sh test.sh 1 2 3

1 2 3
a b c

#/usr/bin/env sh

echo $@

set -- *

echo $@

wayout 寫到：
您好：
謝謝您，想再請教
若 設定set -- * 後，會抓所有參數 補進去
但這會暫留， 一般要如何 取消 -- * 的結果呢?

我有用 set --
但他似乎還有傳遞1個 參數
謝謝!

#!/usr/bin/env sh

set -- *

set --

echo a"$@"b

ab

-- Assign any remaining arguments to the positional parameters.
If there are no remaining arguments, the positional parameters
are unset.

#!/usr/bin/env sh

set -- *

set --

echo 'a'

for name do

echo $name

done

echo 'b'

a
b